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6x^2-84=3x
We move all terms to the left:
6x^2-84-(3x)=0
a = 6; b = -3; c = -84;
Δ = b2-4ac
Δ = -32-4·6·(-84)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-45}{2*6}=\frac{-42}{12} =-3+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+45}{2*6}=\frac{48}{12} =4 $
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